Let S denote the success (getting a '6') and F denote the failure (not getting a '6').
P(A wins in the first throw) = P(S)= 
A gets the throw, when the first throw by A and second throw by B result into failures. Therefore,
P(B wins) = 1 - P(A wins) = 
A can hit a target 4 times in 5 shots, B 3 times in 4 shots, and C 2 times in 3 shots. Calculate the probability that
(i) A B, C all may hit (ii) B, C may hit and A may lose.
A and B toss a coin alternatively till one of them gets a head and wins the game. If A starts the game, find the probability of his winning at his third toss.
Let P(A), 
be the probabilities of A's getting the head and not getting the head respectively.
Then 
Similarly, P(B) = 
Now A starts the game and wins in his third toss i.e., in 5th row
required probability = 
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